MathematicsTypes of Sets and Set OperationsJEE Advanced 1981Easy
Visualized Solution (Hindi)
Understanding the Problem
- Given sets: A1,A2,…,A30 with n(Ai)=5.
- Given sets: B1,B2,…,Bn with n(Bj)=3.
- Union: ⋃Ai=⋃Bj=S.
- Each element of S is in exactly 10 of Ai and 9 of Bj.
The Counting Principle
- Principle: If each element of S belongs to exactly k sets X1,X2,…,Xm, then:
- n(S)=k∑i=1mn(Xi)
Finding n(S) using Ai
- Total elements in Ai (with repetition) =30×5=150.
- Since each element is in 10 sets, n(S)=10150=15.
Setting up the Bj Equation
- Total elements in Bj (with repetition) =n×3=3n.
- Since each element is in 9 sets, n(S)=93n=3n.
Solving for n
- Equating the two values of n(S):
- 3n=15
- n=15×3=45
Key Takeaways
- Key Concept: Double counting principle in Set Theory.
- Formula: n(S)=Repetition factorTotal elements with repetition
- Final Answer: n=45
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