MathematicsTypes of RelationsJEE Main 2004Easy
Visualized Solution (English)
Visualizing the Relation R
- Given Set A={1,2,3,4}
- Relation R={(1,3),(4,2),(2,4),(2,3),(3,1)}
Checking Reflexivity
- A relation is reflexive if (a,a)∈R for all a∈A.
- Here, (1,1)∈/R, (2,2)∈/R, etc.
- Therefore, R is not reflexive.
Checking Symmetry
- A relation is symmetric if (a,b)∈R⟹(b,a)∈R.
- Check pairs:
- (1,3)∈R and (3,1)∈R (Symmetric for this pair)
- (4,2)∈R and (2,4)∈R (Symmetric for this pair)
- But, (2,3)∈R while (3,2)∈/R.
- Conclusion: R is not symmetric.
Checking Transitivity
- A relation is transitive if (a,b)∈R and (b,c)∈R⟹(a,c)∈R.
- Consider (1,3)∈R and (3,1)∈R.
- For transitivity, (1,1) must be in R.
- Since (1,1)∈/R, the relation is not transitive.
Checking Function Property
- A relation is a function if every element in the domain has exactly one image.
- In R, element 2 is related to both 3 and 4.
- (2,3)∈R and (2,4)∈R.
- Since one input has multiple outputs, R is not a function.
Conclusion & Final Answer
- Key Takeaway: To check relation types, test each definition against the given set of pairs.
- Final Result: The relation is not symmetric because (2,3)∈R but (3,2)∈/R.
- Next Challenge: What minimum pairs must be added to R to make it an equivalence relation?
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