MathematicsAdjoint and Inverse of a MatrixJEE Advanced 2006Moderate
Visualized Solution (English)
Defining the Matrix Equation
- Given matrix A=123012001
- Let U=[U1 U2 U3] be a 3×3 matrix.
- We are given AU1,AU2, and AU3.
- By the property of matrix multiplication: AU=[AU1 AU2 AU3]
Constructing Matrix AU
- Substitute the given column vectors into the matrix AU:
- AU=100230231
- Note: This is an upper triangular matrix.
Applying Determinant Properties
- To find ∣U∣, use the property: ∣AU∣=∣A∣⋅∣U∣
- Therefore, ∣U∣=∣A∣∣AU∣
- We need to calculate ∣A∣ and ∣AU∣ separately.
Calculating ∣A∣ and ∣AU∣
- Since A is lower triangular: ∣A∣=1×1×1=1
- Since AU is upper triangular: ∣AU∣=1×3×1=3
- Using ∣A∣⋅∣U∣=∣AU∣⟹1⋅∣U∣=3
- Final value: ∣U∣=3
Finding Matrix U
- To find U, solve U=A−1100230231
- Calculating A−1: A−1=1−2101−2001
- Perform matrix multiplication: U=1−212−1−42−1−3
Sum of Elements of U−1
- Calculate U−1=∣U∣1adj(U)
- U−1=31−1−79−2−560−33
- Sum of elements =31(−1−2+0−7−5−3+9+6+3)=0
Final Quadratic Form Evaluation
- Evaluate XTUX where X=320
- First, UX=1−212−1−42−1−3320=7−8−5
- Then, [3 2 0]7−8−5=21−16+0=5
Key Takeaways
- Key Takeaway 1: Matrix U can be built column-wise if AUi is known.
- Key Takeaway 2: Determinant of triangular matrices is the product of diagonal elements.
- Next Challenge: What happens if matrix A is singular? Can we still find a unique U?
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