MathematicsConjugate and ModulusJEE Advanced 1979Easy
Visualized Solution (English)
Given Equation
- Given equation: x+iy=c+ida+ib
- Objective: Prove (x2+y2)2=c2+d2a2+b2
The Modulus Tool
- Definition of Modulus: For z=x+iy, ∣z∣=x2+y2
- Strategy: Apply the modulus operator to both sides of the given equation.
Applying Modulus to Both Sides
- Taking modulus: ∣x+iy∣=c+ida+ib
Using Modulus Properties
- Property 1: ∣z∣=∣z∣
- Property 2: z2z1=∣z2∣∣z1∣
- Applying properties: ∣x+iy∣=∣c+id∣∣a+ib∣
Substitution and First Squaring
- Substitute values: x2+y2=c2+d2a2+b2
- Squaring both sides: x2+y2=c2+d2a2+b2
Final Squaring and Conclusion
- Squaring again: (x2+y2)2=(c2+d2a2+b2)2
- Final Result: (x2+y2)2=c2+d2a2+b2
- Key Takeaway: Modulus properties are powerful for eliminating imaginary parts in complex identities.
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