MathematicsVarious Forms of Equations of a LineJEE Advanced 2000Moderate
Visualized Solution (Hindi)
Introduction to Manhattan Distance
- Given Points: O=(0,0) and A=(3,2)
- New Distance Definition: d(P,Q)=∣x1−x2∣+∣y1−y2∣
- Objective: Find the locus of P(x,y) such that d(P,O)=d(P,A) in the first quadrant.
Distance from Origin d(P,O)
- For P(x,y) in the first quadrant, x≥0 and y≥0.
- The distance from origin O(0,0) is:
- d(P,O)=∣x−0∣+∣y−0∣=x+y
Distance from Point A(3,2)
- The distance from point A(3,2) is:
- d(P,A)=∣x−3∣+∣y−2∣
The Equidistant Condition
- Equating the distances:
- x+y=∣x−3∣+∣y−2∣
Case 1: y≥2
- Assume y≥2 and x<3:
- x+y=(3−x)+(y−2)
- x+y=1−x+y
- 2x=1⇒x=21
- This forms an infinite ray starting from (21,2) upwards.
Case 2: y<2
- Assume y<2 and x<3:
- x+y=(3−x)+(2−y)
- x+y=5−x−y
- 2x+2y=5⇒x+y=25
- This forms a finite line segment from (25,0) to (21,2).
Final Locus and Summary
- Final Set: Union of the segment x+y=25 for y∈[0,2] and the ray x=21 for y≥2.
- Key Takeaway: Manhattan distance results in piecewise linear loci.
- Next Challenge: What is the shape of a 'circle' defined by d(P,O)=r?
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