Sets and Relations Questions

MathematicsSets and Relations26 Questions Found

MathematicsCartesian Product of SetsJEE Main 2013Easy

View in:English Hindi

Let A and B two sets containing 2 elements and 4 elements respectively. The number of subsets of $A \times B$ having 3 or more elements is

(A)

256

(B)

220

(C)

219

(D)

211

Answer:C

MathematicsTypes of Sets and Set OperationsJEE Main 2014Easy

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The statement $\sim (p \leftrightarrow\sim q)$ is:

(A)

a tautology

(B)

a fallacy

(C)

eqivalent to

p \leftrightarrow q

(D)

equivalent to

\sim p \leftrightarrow q

Answer:C

MathematicsTypes of Sets and Set OperationsJEE Main 2014Easy

View in:English Hindi

If $X = {4^{n} - 3 n - 1 : n \in N}$ and $Y = {9 (n - 1) : n \in N}$ , where N is the set of natural numbers, then $X \cup Y$ is equal to:

(A)

(B)

(C)

(D)

Y - X

Answer:B

MathematicsTypes of Sets and Set OperationsJEE Main 2015Easy

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The negation of $\sim s \lor (\sim r \land s)$ is equivalent to :

(A)

s \lor (r \lor \sim s)

(B)

s \land r

(C)

s \land \sim r

(D)

s \land (r \land \sim s)

Answer:B

MathematicsTypes of Sets and Set OperationsJEE Main 2015Easy

View in:English Hindi

Let A and B be two sets containing four and two elements respectively. Then the number of subsets of the set $A \times B$ , each having at least three elements is :

(A)

275

(B)

510

(C)

219

(D)

256

Answer:C

MathematicsTypes of Sets and Set OperationsJEE Main 2016Easy

View in:English Hindi

The Boolean Expression $(p \land \sim q) \lor q \lor (\sim p \land q)$ is equivalent to:

(A)

p \lor q

(B)

p \lor \sim q

(C)

\sim p \land q

(D)

p \land q

Answer:A

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } Let A and B two sets containing 2 elements and 4 elements respectively. The number of subsets of A×B having 3 or more elements is

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } The statement ∼(p↔∼q) is:

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } If X={4n−3n−1:n∈N} and Y={9(n−1):n∈N}, where N is the set of natural numbers, then X∪Y is equal to:

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } The negation of ∼s∨(∼r∧s) is equivalent to :

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } Let A and B be two sets containing four and two elements respectively. Then the number of subsets of the set A×B, each having at least three elements is :

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } The Boolean Expression (p∧∼q)∨q∨(∼p∧q) is equivalent to:

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } Let A and B two sets containing 2 elements and 4 elements respectively. The number of subsets of A×B having 3 or more elements is

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } The statement ∼(p↔∼q) is:

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } If X={4n−3n−1:n∈N} and Y={9(n−1):n∈N}, where N is the set of natural numbers, then X∪Y is equal to:

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } The negation of ∼s∨(∼r∧s) is equivalent to :

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } Let A and B be two sets containing four and two elements respectively. Then the number of subsets of the set A×B, each having at least three elements is :

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } The Boolean Expression (p∧∼q)∨q∨(∼p∧q) is equivalent to:

Let A and B two sets containing 2 elements and 4 elements respectively. The number of subsets of $A \times B$ having 3 or more elements is

The statement $\sim (p \leftrightarrow\sim q)$ is:

If $X = {4^{n} - 3 n - 1 : n \in N}$ and $Y = {9 (n - 1) : n \in N}$ , where N is the set of natural numbers, then $X \cup Y$ is equal to:

The negation of $\sim s \lor (\sim r \land s)$ is equivalent to :

Let A and B be two sets containing four and two elements respectively. Then the number of subsets of the set $A \times B$ , each having at least three elements is :

The Boolean Expression $(p \land \sim q) \lor q \lor (\sim p \land q)$ is equivalent to:

Let A and B two sets containing 2 elements and 4 elements respectively. The number of subsets of $A \times B$ having 3 or more elements is

The statement $\sim (p \leftrightarrow\sim q)$ is:

If $X = {4^{n} - 3 n - 1 : n \in N}$ and $Y = {9 (n - 1) : n \in N}$ , where N is the set of natural numbers, then $X \cup Y$ is equal to:

The negation of $\sim s \lor (\sim r \land s)$ is equivalent to :

Let A and B be two sets containing four and two elements respectively. Then the number of subsets of the set $A \times B$ , each having at least three elements is :

The Boolean Expression $(p \land \sim q) \lor q \lor (\sim p \land q)$ is equivalent to: