The fourth power of the common difference of an arithmetic progression with integer entries is added to the product of any four consecutive terms of it. Prove that the resulting sum is the square of an integer.
Comprehension Passage
Let A1,G1,H1 denote the arithmetic, geometric and harmonic means, respectively, of two distinct positive numbers. For n≥2, Let An−1 and Hn−1 have arithmetic, geometric and harmonic means as An,Gn,Hn respectively.
Question 1:
Which one of the following statements is correct ?
(D)
G1<G3<G5<… and G2>G4>G6>…
Question 2:
Which one of the following statements is correct ?
(C)
A1>A2>A5>… and A2<A4<A6<…
(D)
A1<A3<A5<… and A2>A4>A6>…
Question 3:
Which one of the following statements is correct?
(C)
H1>H3>H5>… and H2<H4<H6<…
(D)
H1<H3<H5<… and H2>H4>H6>…
Comprehension Passage
Let Vr denote the sum of first r terms of an arithmetic progression (A.P.) whose first term is r and the common difference is (2r−1). Let Tr=Vr+1−Vr−2 and Qr=Tr+1−Tr for r=1,2,…
Question 3:
Which one of the following is a correct statement ?
(A)
Q1,Q2,Q3,… are in A.P. with common difference 5
(B)
Q1,Q2,Q3,… are in A.P. with common difference 6
(C)
Q1,Q2,Q3,… are in A.P. with common difference 11
mn squares of equal size are arranged to from a rectangle of dimension m by n, where m and n are natural numbers. Two squares will be called 'neighbours' if they have exactly one common side. A natural number is written in each square such that the number written in any square is the arithmetic mean of the numbers written in its neighbouring squares. Show that this is possible only if all the numbers used are equal.
Use mathematical Induction to prove : If n is any odd positive integer, then n(n2−1) is divisible by 24.
If a>0,b>0 and c>0, prove that (a+b+c)(a1+b1+c1)≥9.
Let p be the first of the n arithmetic means between two numbers and q the first of n harmonic means between the same numbers. Show that q does not lie between p and (n−1n+1)2p.
Let a,b,c be positive real numbers such that b2−4ac>0 and let α1=c. Prove by induction that αn+1=b2−2a(α1+α2+....+αn)aαn2 is well-defined and αn+1<2αn for all n=1,2,... (Here, 'well-defined' means that the denominator in the expression for αn+1 is not zero.)
Let a,b be positive real numbers. If a,A1,A2,b are in arithmetic progression, a,G1,G2,b are in geometric progression and a,H1,H2,b are in harmonic progression, show that H1H2G1G2=H1+H2A1+A2=9ab(2a+b)(a+2b).
If a,b,c are in A.P., a2,b2,c2 are in H.P., then prove that either a=b=c or a,b,−c/2 form a G.P.